Questions tagged [copula]

A copula is a multivariate distribution with uniform marginal distributions. Copulas are mostly used to represent or to model the structure of dependence between random variables, separately from the marginal distributions.

A copula is a multivariate distribution with uniform marginal distributions. Copulas are mostly used to represent or to model the structure of dependence between random variables, separately from the marginal distributions.

Let $F(y_1,...y_n)$ be the multivariate CDF of a random vector $Y$. We say the function $C(u_1,...,u_n)$ is the copula for the joint distribution of $Y$, when its marginals, $F(Y_j)$ are uniformly distributed.

The copula determines the distribution of every function of $Y$ that is invariant to univariate monotone transformations of $Y$. This means that the joint distribution of the ranks $r_1,...,r_n$ of an i.i.d. sample $Y_1, ..., Y_n$ from $F$ is entirely determined by $C$ (if the margins are absolutely continuous).

This is based on Sklar's theorem which shows that all multivariate distributions contain a copula, and how joint distributions are formed by coupling together marginal distributions with a copula. If you take a continuous multivariate distribution and apply the Probability Integral Transform to each margin, the resulting multivariate distribution has uniform margins and will be a copula.

Copulas are widely used in many application areas including finance, insurance, actuarial science, biostatistics, hydrology and weather research.

Reference: http://en.wikipedia.org/wiki/Copula_%28probability_theory%29

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What is copula transformation

I have seen that copula transformation changes my sample space to the range of $[0 \; 1]^d$ where d is the number of dimensions. Can anyone explain me about copula transformation?
user34790
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Copula is not unique if the margins in not continuous

The copula is a very interesting tool to describe the dependence structure. However, I read that if the margins are continuous then copula is unique. However, if margins are discrete then copula is not unique. I cannot understand this two points.…
user204564
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What will Frank copula tell me?

As we all know, there are several copula functions, each with its own ability to describe specific dependency structure. I wonder what the Frank copula can tell me. For example, Clayton copula is a lower tail dependency function; that is, the lower…
Maryam
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Copula Calibration

I've developed a step by step procedure for estimating a copula based upon 2 stock time series returns but I don't understand and have not implemented one step that is discussed in most of the copula literature. Could someone please show me how to…
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Which parametric family could describe these asymmetric copulas?

In my recent project I keep encountering asymmetric copulas like this: However, most of the common parametric copulas I could find are symmetric. While there are some resources on asymmetric copulas I can't figure out if any of them would be a good…
Jannis
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In definition of gaussian copula does the marginals also have to be gaussian?

I am quite new to this copula idea. In particular I am confused about the definition of a Gaussian copula. For a copula to be a Gaussian copula does the marginals have to Gaussian as well? Or it can be of any distribution? From the wikipedia page it…
xiaodai
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Does this copula have a name?

Let \begin{equation} c(u_1,u_2|k) = k\,\big((1-u_1)\,(1-u_2)\big)^{k-1}\, _2F_1\!\left(1-k,1-k;1; \frac{u_1\,u_2}{(1-u_1)\,(1-u_2)}\right) , \end{equation} where $k \in \{1, 2, \ldots\}$ and where $_2F_1$ is the hypergeometric function. The…
mef
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Copula compatibility problem

Suppose I have a 3-Copula which I would like to construct with two 2-Copula's, as the following construct: $$ C_2(u, C_1(v,w)) = C(u,v,w) $$ My question is, if $C$ is known to be a valid copula (i.e. follows the properties such as groundedness, etc…
Kiran K.
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What is this copula?

I have a bivariate sample in the [0,1] square for which I am trying to find the copula that best describes it. (I am new to copulas.) So far, I have tried all classes in the "copula" R package. Using ML, the best fit was the t-Copula. However, this…
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Differentiating a copula joint distribution

I am trying to derive the differentiation of joint copula from this paper http://www.nicksun.fun/assets/ms_references/madsen2009.pdf, which is done in equation (4.3). To summarize I fail to understand why the derivative of $z'\Sigma^{-1}z$ is…
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How to fit data generated by Gaussian copula with Bernoulli distribution margins?

I planned to fit two Bernoulli random variables X, Y with a Gaussian copula, where X~Bernoulli(p1) and Y~Bernoulli(p2) (take p1= 0.2 and p2=0.5 for example) and the parameter of Gaussian copula (ρ) is 0.5. Then the data generation process…
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The range of Kendall tau for the Frank copula

Considering that θ in Frank copula is a function of the Kendall's tau as follows: I would like to know the range of Kendall's tau that can be used in the Frank copula. Thank you in advance for any helps.
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Regular Vine Copula Construction

In 3 variables regular vine construction, we have $$f(x_1,x_2,x_3) = \text{marginal}\times\text{unconditional pairs}\times\text{conditional pairs}=f_3(x_3)f_2(x_2)f_1(x_1)\times c_{12}(F_1(x_1),F_2(x_2))c_{23}(F_2(x_2),F_3(x_3))\times…
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Why aren't copulas unique for non-continuous random variables?

I have read from the Sklar's theorem that for continuous random variables, then copula is unique. I really do not understand why? Could someone please explain to me why the copula not unique if the random variables are not continuous? If there is a…
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Why do Gaussian copula does not have a closed form? hence, why numerical estimation is needed?

I am working on Gaussian copula. I always read that, Elliptical copulas do not have closed form expression and hence, the numerical estimation is needed. I really do not understand what does closed form means for Gaussian copula. And Why it does not…
Maryam
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