No.
There's no clear/consistent ways to make an object invisible (Mirage Arcane can render objects invisible but is very unique in general; Invisibility + True Polymorph is an arguable corner case at most), so this is based on applying invisibility rules as they apply to creatures to objects.
Here are the main pertinent rules:
A creature you touch becomes invisible until the spell ends. Anything the target is wearing or carrying is invisible as long as it is on the target's person. The spell ends for a target that attacks or casts a spell. (Invisibility, the spell)
An invisible creature is impossible to see without the aid of magic or a special sense. For the purpose of hiding, the creature is heavily obscured. The creature's location can be detected by any noise it makes or any tracks it leaves. (Invisible, the condition)
You touch one object that is no larger than 10 feet in any dimension. Until the spell ends, the object sheds bright light in a 20-foot radius and dim light for an additional 20 feet. The light can be colored as you like. Completely covering the object with something opaque blocks the light. The spell ends if you cast it again or dismiss it as an action. (Light, the spell)
Invisible light sources produce visible light.
This has been asked before, with consensus pointing toward "invisible light sources still produce light," which is in line with a Jeremy Crawford tweet:
The invisibility spell doesn't prevent you or your gear from emitting light, yet that light makes you no less invisible. The light appears to be coming from the air. Spooky! #DnD
Light is not blocked by an invisible barrier.
An invisible creature is not opaque, by definition: they are completely transparent. This means that they don't cast shadows and they don't block light. The spell explicitly calls out that it needs to be blocked by something opaque.
Either way, whether or not the invisible container would make its contents invisible, the light will be emitted. The invisible container cannot block the light and the light source, whether or not it's still visible, will continue to emit light. This question and its top answer also feels pertinent here.