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You can use +,-,*,/,^,! and sqrt operations (no concatenation) and all numbers must be used once and only once. for example, 75 can be made by $3×(4!+2-1)$ and $81=(2-1)×3^4$

I've been trying to reach 100 and this appears to be the first impossible number. Similar using 1 to 5, 202 appears to be the first impossible number.

Parcly Taxel
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Ri Ignis
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    For your comment about 202, you can do $202=(5*3^4-1)/2$ – ThomasL Nov 12 '22 at 19:30
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    A refined version of my program gave solutions for the 1–5 problem for all but 6 numbers in 0–1000: 892, 917, 919, 926, 941, 942. – Parcly Taxel Nov 13 '22 at 01:24
  • Possible duplicate of https://puzzling.stackexchange.com/questions/107527/calculation-the-hard-way Its a really nice puzzle to play with students to teach them how to do math in their head :) – Nurator Nov 14 '22 at 07:14

2 Answers2

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I wrote a program and it returned this: $$76=4×\sqrt{(3!)!/2+1}$$

The output (using reverse Polish notation) of a refined version of my program, capable of handling the 1–5 problem, can be found here. Only 85, 86 and 93 are impossible for the 1–4 problem from 0 to 100, while 892, 917, 919, 926, 941 and 942 are impossible for the 1–5 problem from 0 to 1000.

Parcly Taxel
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This is potentially not quite in the spirit of the puzzle, but how about:

we try a little concatenation? You said we can use "and".

=(1&3^2) x 4 = 76
=(1&9) x 4 = 76
=19 x 4 = 76

will
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