Create number 985 using 1 3 5 7 9

Question

Use $1, 3, 5, 7, 9$ in any order to make number $985$:

1. You must use all $5$ digits $1, 3, 5, 7, 9$ exactly once. You can make multi-digit numbers out of the numbers, e.g. $13$ or $975$.

2. $+, -, *, /, (), \text{^}, \text{and }!$ (factorial) are the only allowed functions. Example: factorial may be used more than once, e.g. $(3!)!=720$ is acceptable.

Answer 1

A small modification to the program from this answer of mine yielded this:

$$985=(3!)!+\frac{7!-5}{19}$$

Answer 2

Below equation should give desired result:

$$\mod(5, 3!) * 197 = 5 * 197 = 985$$

Answer 3

Slightly cheeky:

$-5-\dfrac{(-9)!}{(1-3!-7)!}$

"Justification"

$\displaystyle\lim_{x\to-n} \frac{\Gamma(x+1)}{\Gamma(x)} = -n$

The same method allows for a variation of @Aman's answer

$-197 \times (-5)! / (-(3!))!$

Answer 4

A cheeky, but ingenious way:

We do $7+1$ to make $8$ and then use $9$, $8$ (The number from the previous equation) and $5$ to make $985$.
Here's the cheeky part: We use the last digit ($3$) by doing $x = 3$. Then we can do $985 + (x - x)$ to get $985$.
$x = 3$ isn't a function!

Full equation ($answer$ means answer):

$$answer = (985) + (x - x), x = 3, 1 + 7 = 8$$