I saw this date command:
date -d @1332468005 '+%Y-%m-%d %H:%M:%S'
Resulting in :
2012-03-22 22:00:05
How can I convert it back from 2012-03-22 22:00:05 to 1332468005 with bash shell?
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Kusalananda
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Uncelvel
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3 Answers
26
man date will give you the details of how to use the date command.
To convert long date in standard format into Unix epoc time (%s):
date -d '2012-03-22 22:00:05 EDT' +%s
David
- 622
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1It just didn't work for date like 'Пн 17 окт 2022 15:49:09 EEST' – outoftime Oct 17 '22 at 13:48
2
On BSD OS (FreeBSD, OpenBSD, NetBSD), date doesn't support -d flag. Use instead -j flag ("Parse the provided date and time and display the result without changing the clock") and strftime string format.
$ TZ=UTC date -j -f "%Y-%m-%d %H:%M:%S" "2012-03-22 22:00:05" +%s
1332453605
lcheylus
- 193
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This may have been better suited as an update to the already existing (and virtually identical) answer that deals with macOS? – Kusalananda Nov 11 '23 at 09:46