How do you code the following logic gate circuits?

Question

How do you code the following logic gate diagrams?

My current attempts:

\begin{circuitikz}
        %Top OR Gate
        \draw
        (0,-1) 
        node[label = left:$A$] {}
        to [short]
        (1,-1)
        node[american or port, anchor = in 1] (or1){}
        (or1.in 2)
        -- ++(-1,0)
        node[label = left:$B$] {}
        to[short]
        (or1.in 2)
        (or1.in 2)
        -- ++(-1,0)
        (or1.out)
        to[short] (2.5,-3)
        node[american and port, anchor = in 1] (and1){}
        (and1.in 2)
        -- ++(-2.5,0)
        node[label = left:$C$] {}
        (0,-5) 
        node[label = left:$D$] {}
        to [short]
        (2.5,-5)
        node[american not port, anchor = in 1] (not1){}
        (and1.out)
        to[short] (4,-4)
        node[american or port, anchor = in 1] (or2){}
        (and1.in 2)
        (not1.out)
        to[short] (4, 52 |- or2.in 2)
        (or2.out)
        -- ++(1,0)
        node[label = right:$X$] {}
        %labels
        (or1.out)
        node[label = right:$X_1$] {}
        (and1.out)
        node[label = right:$X_2$] {}
        (xor2.out)
        node[label = right:$X_3$] {}
        \end{circuitikz}

I am not confident with complex logic gates configurations. But code has been entered as an attempt — Antonia Ponton, Feb 26 '22 at 07:44
See also https://tex.stackexchange.com/questions/479365/how-to-invert-logic-gate-input-in-circuitikz https://tex.stackexchange.com/questions/550220/boolean-circuit-using-circuitikz https://tex.stackexchange.com/questions/536195/how-to-offset-circuitikz-logic-gates-so-that-the-input-and-output-ports-line-up — Rmano, Feb 26 '22 at 11:46
It is much better if you post compilable code (look at my answer). I added a drawing of your code, to make the question more interesting... — Rmano, Feb 26 '22 at 12:50
Since you have some responses below that seem to answer your question, please consider marking one of them as ‘Accepted’ by clicking on the tickmark below their vote count (see How do you accept an answer?). This shows which answer helped you most, and it assigns reputation points to the author of the answer (and to you!). It's part of this site's idea to identify good questions and answers through upvotes and acceptance of answers. — Rmano, Mar 01 '22 at 20:57

Rmano · Answer 1 · 2022-02-26T19:39:12.227

This is a possible solution; I heavily commented the code to show the reasoning behind it. I do not say this is the only way to do it; but notice that I use explicit coordinates (numbers) only where needed, so changing just one of it will change the spacing of the circuit, keeping it coherent.

\documentclass[margin=1cm]{standalone}
\usepackage{circuitikz}
% IEEE standard ports are much nicer
\ctikzset{logic ports=ieee}
\begin{document}
\begin{tikzpicture}
    % let's start with the first port. The ++(1,0) will select how much to the right
    % from the connection is. Change this to have more space, the rest will follow.
    \draw (0,0) coordinate (start) node[left]{$A$} -- ++(1,0) 
        nodeor port, anchor=in 1{} (or1.out) node[right]{$X_1$};
    % second input, below the first one
    % (X -| Y) means: go horizontal from X, vertical from Y
    \draw (or1.in 2) -- (or1.in 2 -| start) node[left]{$B$};
    % the second port will be below and to the right the first one.
    \draw (or1.out) -- ++(0,-1) nodeand port, anchor=in 1{}
        (and1.out) node[right]{$X_2$};
    \draw (and1.in 2) -- (and1.in 2 -| start) node[left]{$C$};
    % now, if you really want the not at the same level of and1...
    % we move down for input 2 of and1 without stroking
    \draw (and1.in 2) ++(0,-1) node not port, anchor=in{}
        % we want the X3 label at the same x-position that X2
        (not1.out -| and1.out) node[right]{$X_3$};
    \draw (not1.in) -- (not1.in -| start) node[left]{$D$};
    % trick here: put the next or midway from and1 and not1
    \draw ($(and1.out)!0.5!(not1.out)$) ++(2,0) nodeor port{}
        (or2.out) node[right]{$X$};
    % let do a nice connection here: |- means go vertically then horizontally
    \draw (and1.out) |- (or2.in 1);
    % a little bit trickier for the not, because it's shorter: let's go
    % horizontally  until the above kink, and then |-
    \draw (not1.out) -- (not1.out -| and1.out) |- (or2.in 2);
\end{tikzpicture}
\end{document}

How do you code the following logic gate circuits?

1 Answers1