How to convert _ to \_

Question

In this question, answers suggested using \newcommand{\code}[1]{\texttt{#1}} to type in a stylized code font. This works rather nicely, however, I am trying to write about code in a website, where the format/convention for naming functions is to have them be multiple_words_long_with_underscores_representing_spaces. However, I'm rather lazy, and would rather not have to repeatedly preface each underscore with a backslash. I realize I could use find-replace-methods, but is there a latex method to add this into my \newcommand{\code}[1]{\texttt{#1}} shortcut?

score 3 · Accepted Answer · answered Sep 19 '19 at 15:33

3

Consider using listings' \lstinline (experimental):

\documentclass{article}

\usepackage{listings}
\lstset{
  basicstyle = \ttfamily
}
\let\code\lstinline

\begin{document}

Some regular text.
Some \code{code} inline.
Then some \code{multiple_words} code word.

\end{document}

answered Sep 19 '19 at 15:33

Werner

603,163

3

Why not just \detokenize? – daleif Sep 19 '19 at 15:37
@daleif: As in Underscores in words (text)? ;) Code is typically formatted using listings; that's my motivation for using it. – Werner Sep 19 '19 at 16:25
1

@daleif without any spaces in the name, \detokenize will not linebreak. That may or may not be an issue for the OP. – Steven B. Segletes Sep 19 '19 at 16:57
@StevenBSegletes will listings break lines from inline? – daleif Sep 19 '19 at 19:56

score 0 · Answer 2 · answered Sep 19 '19 at 15:48

\documentclass{article}
\newcommand\ustexttt[1]{\bgroup\ttfamily\ustextttaux#1\relax\relax}
\def\ustextttaux#1#2\relax{\ifx_#1\_\else#1\fi
  \allowbreak
  \ifx\relax#2\relax\def\next{\egroup}\else\def\next{\ustextttaux#2\relax}\fi
  \next}
\begin{document}
Here is an example
\ustexttt{multiple_words_long_with_underscores_representing_spaces}
of converted underscores, with autobreak enabled.
\end{document}

If you only want linebreaking following underscores, you can move the \allowbreak inside the prior \ifx block, following the \_.

How to convert _ to \_

2 Answers2