I'm working on a tikz picture, and failed to vertical align tikz pictures in one beamer frame. I did many google search and finally found it may be to do with inner sep of matrix. Is is possible to get the inner sep in figure 1, and used it in figure 3?
There is another problem of absolute position, if the matrix in figure 3 grows from one row to two rows, or from no arrows to have arrows, the absolute position of 3 figures all changes.
(In fact what I actually want to do is to make animation which forms a dependency tree from an initial state to a terminal state. The transitions between states are some what complicated, so I plan to draw each transition in one page, and convert one page to one static picture, and finally convert all static pictures into a gif.)
\documentclass{beamer}
\setbeamersize{text margin left=0pt}
\usepackage{tikz}
\usetikzlibrary{arrows, chains, fit, quotes, matrix, positioning}
\usepackage{mathtools}
\begin{document}
\tikzstyle{every picture}+=[remember picture]
\begin{frame}[fragile]
\begin{tikzpicture}[
node distance = 5mm,
start chain = A going right,
txt/.style = {text height=2ex, text depth=0.25ex, on chain},
edge1/.style = {draw, -stealth', dotted, gray},
edge2/.style = {draw, -stealth'},
]
%\draw [help lines] (-1,-1) grid (10,2);
\node [txt] {Configuration $C_i$};
\node [txt] {I};
\node [txt] {booked};
\node [txt] {a};
\node [txt] {ticket};
\node [txt] {to};
\node [txt] {China};
%
\node (f1) [rounded corners=3mm, line width=1mm, draw=blue!50, inner sep=0pt,
label={[blue!50]below:Stack $\delta$},
fit=(A-2) (A-3)] {};
\node (f2) [rounded corners=3mm, line width=1mm, draw=green!70!black, text=green!70!black, inner sep=0pt,
label={[green!70!black]below:Buffer $\beta$},
fit=(A-4) (A-7)] {};
%
\path (A-3) edge[edge2,bend right=70, "nsubj" '] (A-2)
(A-3) edge[edge1,bend left=90, "dobj" ] (A-5)
(A-5) edge[edge1,bend right=70, "det" '] (A-4)
(A-5) edge[edge1,bend left=70, "prep" ] (A-6)
(A-6) edge[edge1,bend left=70, "pobj" ] (A-7);
\end{tikzpicture}
\begin{tikzpicture}[
node distance = 5mm,
start chain = B going right,
txt/.style = {fill=red!50, on chain, text=white},
title/.style = {on chain},
]
\node [title] {Action $C_i \xrightarrow{a_i} C_{i+1}$};
\node [txt] {SHIFT};
\node [txt] {LEFT\_ARC};
\node [txt] {RIGHT\_ARC};
\end{tikzpicture}
\begin{tikzpicture}
\matrix (m) [matrix of nodes,row sep=1em,column sep=1.3em,
% How can I get the inner sep of (A-1) or (B-1),
% so that the tree pictures are vertical aligned?
inner sep=0em,
]
{
Transition sequence & $C_0$ & $C_1$ & $C_2$ & $C_3$ & $C_4$ & $C_5$ \\
& {\phantom{$C_0$}} & $C_6$ & $C_7$ & $C_8$ & \\
};
\path[-stealth]
(m-1-2) edge node [above] {$a_0$} (m-1-3)
(m-1-3) edge node [above] {$a_1$} (m-1-4)
(m-1-4) edge node [above] {$a_2$} (m-1-5)
(m-1-5) edge node [above] {$a_3$} (m-1-6)
(m-1-6) edge node [above] {$a_4$} (m-1-7)
(m-2-2) edge node [above] {$a_6$} (m-2-3)
(m-2-3) edge node [above] {$a_7$} (m-2-4)
(m-2-4) edge node [above] {$a_8$} (m-2-5);
\end{tikzpicture}
\end{frame}
\end{document}
The example in the beamer is adapted from slides of Slav Petrov. Original picture is
What I get now is
EDIT:
As @Ignasi suggested, I used t option in documentclass, the absolute position of 3 figures nows looks much better, except figure 3's position is still minor changed.
tindocumentclassorframe, the frame contents will be top aligned instead of default central alignment. It's this central alignment which moves everything when you changes matrix from one to two lines. – Ignasi Sep 01 '16 at 09:51