Suppose I have two tex files file1.tex and file2.tex. I want to join them in another tex file. I have tried to do this with the following one :
\documentclass{book}
\begin{document}
\chapter{Chapter-1}
\section{Section-1}
\begin{theorem}
Theorem 1.1.1
\end{theorem}
\input{file1}
\input{file2}
\begin{lemma}
Lemma
\end{lemma}
\end{document}
But this shows error. Is it possible to do so ?
file1.tex is given below :
\input{mks}
\begin{document}
\begin{center}
{\textbf{\huge{Abstract Algebra}}}
\end{center}
\noindent\large{\textbf{Part-B}}
\begin{enumerate}
\item Consider a group $G$. Let $Z(G)$ be its centre. i.e.,$Z(G)=\{g \in G : gh=hg \mbox{~for all~} h \in G\}$. For $n \in \mathbf{N}$, the set of
positive integers , define $J_n=\{(g_1,\dots,g_n)\in Z(G)\times \dots \times Z(G) : g_1\dots g_n=e\}.$ As a subset of the direct product group
$G\times \dots \times G$($n$ times direct product of the group $G$), $J_n$ is
\begin{enumerate}
\item not necessarily a subgroup.
\item a subgroup but not necessarily a normal subgroup.
\item a normal subgroup.
\item isomorphic to the direct product $Z(G)\times \dots \times Z(G)$($(n-1)$ times).
\end{enumerate}
\item Let $G$ be a group of order $77$. Then the center of $G$ is isomorphic to
\begin{enumerate}[(a)]
\begin{multicols}{4}
\item $\mathbf{Z}_{(1)}$
\item $\mathbf{Z}_{(7)}$
\item $\mathbf{Z}_{(11)}$
\item $\mathbf{Z}_{(77)}$
\end{multicols}
\end{enumerate}
\end{enumerate}
\end{document}
where mks.tex is :
\documentclass[11pt,twoside,a4paper]{article}
\usepackage{amsthm,amsmath,amssymb,graphicx}
\usepackage{enumerate}
\usepackage[margin=0.45in]{geometry}
\usepackage{multicol}
\usepackage{tikz}
\DeclareMathOperator{\rank }{rank }
\DeclareMathOperator{\trace }{trace }
\DeclareMathOperator{\lcm }{lcm }
\DeclareMathOperator{\nullity }{nullity }
and file2.tex is :
\documentclass{book}
\usepackage[a4paper,margin=.5in]{geometry}
\usepackage{amsthm,xypic,graphicx}
\theoremstyle{plain}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\theoremstyle{definition}
\newtheorem*{example}{Example}
\newtheorem{definition}{Definition}
\theoremstyle{remark}
\newtheorem*{remark}{Remark}
\begin{document}
\markboth{Right}{Left}
\chapter{First Chapter}
\section{Section 1.1}
\begin{theorem}
Theorem
\end{theorem}
\begin{lemma}
lemma1
\end{lemma}
\begin{theorem}
Theorem
\end{theorem}
$$
\xymatrix{& S\ar@{-}[ld]\ar@{-}[rd] &\\
\{0,a,b,s\}\ar@{-}[d] & &\{0,c\}\ar@{-}[ldd]\\
\{0,a\}\ar@{-}[rd] & & \\
& \{0\} &
}
$$
\begin{center}
figure A.1 : chosen subsets of $S$ see book b119
\end{center}
$$
\xymatrix{ h_{C}(C) \ar[r]^{\eta(C)}\ar[d]^{h_C(f)} & T(C)\ar[d]^{T(f)} \\
h_C(X)\ar[r]^{\eta(X)} & T(X)
}
$$
\begin{center}
figure B.1 : commutativity of the rectangle
\end{center}
$$
\xymatrix{(h_C,T)\ar[rr]^{\theta= \theta_{C,T}}\ar[d]^{N_*(\alpha)} & & T(C)\ar[d]^{\alpha(C)}\\
(h_C,S)\ar[rr] & & S(C)
}
$$
\begin{center}
figure B.3 : commutativity of the rectangle
\end{center}
$$
\xymatrix{(h_C,T)\ar[rr]^{\theta_C= \theta_{C,T}}\ar[d]^{N_*(f)} & & T(C)\ar[d]^{T(f)}\\
(h_D,T)\ar[rr]^{\theta_D=\theta{D,T}} & & T(D)
}
$$
\begin{center}
figure B.4 : commutativity of the rectangle
\end{center}
$$
\xymatrix{h_C(C)\ar[r]^{\eta_{(C)}}\ar[d]^{h_C(f)} & & T(C)\ar[d]^{T(f)}\\
h_C(D)\ar[rr]^{\eta_{(D)}} & & T(D)
}
$$
\begin{center}
figure B.5 : commutativity of the rectangle
\end{center}
$$
\xymatrix{A(U)\ar[rr]^{h(U)}\ar[d]^{r_{_{V,U}}} & & B(U)\ar[d]^{T_{U,V}}\\
A(V)\ar[rr]^{h(V)} & & B(V)
}
$$
\begin{center}
figure B.6 : commutativity of the rectangle
\end{center}
\end{document}
file1andfile2? What are the errors? – Paul Pichaureau May 01 '13 at 07:12