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I have two lists I produce using the following commands:

  1. find . -type f -name config.php -exec ls {} \;

  2. find . -type f -name config.php -exec grep --files-with-matches some_string {} \; | sort

How could I pipe the lists into com -23 so I can see those entries from list1 that aren't contained in list2?

Kamil Maciorowski
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Nick Weavers
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  • You didn't specify your shell. If the linked question is not helpful (e.g. if you're using a shell with no support for process substitution) then please [edit] the question, state your shell and the fact you can't use process substitution. We will reopen the question then. – Kamil Maciorowski May 22 '19 at 15:51
  • Few things about your specific approach: (1) Are you sure you need -exec ls {} \;? I expect -print (or nothing at all) to generate basically the same output. (2) How about grep --files-without-match in the first place? Piping to comm may be unnecessary (compare XY problem). – Kamil Maciorowski May 22 '19 at 16:14
  • Thanks for pointing at the solution. My shells was bash so it is appropriate and it worked. – Nick Weavers May 22 '19 at 16:25
  • Yes, the -exec ls {} ; was unnecessary... I removed it. The --files-without-match would not have given the same result, but thank you for the suggestions. – Nick Weavers May 22 '19 at 16:29

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