Starting an application from command line with fixed dimensions and starting position

Asked Oct 22 '18 at 10:55

Active Oct 22 '18 at 10:55

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How can I start an exe file with a fixed width, height, x and y positions from the command line?

I would expect something like this to work:

MyApp.exe --width 800 --height 600 --x 200 --y 0

Is there a set of universal parameters available for all applications?

asked Oct 22 '18 at 10:55

gAMBOOKa

Possible duplicate of Is there a way to resize a window to specific sizes (eg.800x600, 1024x768..)? – Sandeep Oct 22 '18 at 12:59
@Sandeep All those answers require third-party tools. I am looking for a cmd only code. – gAMBOOKa Oct 22 '18 at 13:03
No universal built in option available as of now. I wrote some 8~10 lines of code with one Win API call and built one utility for my testing. – Sandeep Oct 22 '18 at 13:08
@Sandeep Would you mind sharing your code? Perhaps I, or someone else could have use for it. – gAMBOOKa Oct 22 '18 at 13:25
Not sure if it is good to post whole code as answer when it is not actually answering your question. I used C# and imported MoveWindow function from user32.dll. Called Process.GetProcessesByName(appTitle) to get process object and handle. And called MoveWindow(process.MainWindowHandle, x, y, width, height, true) to set windows position and size. You can get more details here. – Sandeep Oct 22 '18 at 13:41
You can get some sample code here – Sandeep Oct 22 '18 at 13:43
Related: Setting window size and position in PowerShell 5 and 6 – JosefZ Oct 22 '18 at 13:54
If you wish only to use standard Windows applications, this is possible by using either PowerShell or VBScript. – harrymc Oct 22 '18 at 15:41

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