Questions tagged [regularization]

Inclusion of additional constraints (typically a penalty for complexity) in the model fitting process. Used to prevent overfitting / enhance predictive accuracy.

Regularization refers to the inclusion of additional components in the model fitting process that are used to prevent overfitting and/or stabilize parameter estimates.

Parametric approaches to regularization typically add terms to the training error or MLE objective function that penalize model complexity, in addition to the standard data misfit terms (e.g. Ridge Regression, LASSO). This penalty can be interpreted as arising from a prior on the parameter vector in the framework of Bayesian MAP estimation.

Non-parametric regularization techniques include dropout (used in deep learning) and truncated-SVD (used in linear least squares).

Synonyms include: penalization, shrinkage methods, and constrained fitting.

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What is regularization in plain english?

Unlike other articles, I found the wikipedia entry for this subject unreadable for a non-math person (like me). I understood the basic idea, that you favor models with fewer rules. What I don't get is how do you get from a set of rules to a…
Meh
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Why is the regularization term *added* to the cost function (instead of multiplied etc.)?

Whenever regularization is used, it is often added onto the cost function such as in the following cost function. $$ J(\theta)=\frac 1 2(y-\theta X^T)(y-\theta X^T)^T+\alpha\|\theta\|_2^2 $$ This makes intuitive sense to me since minimize the cost…
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How does regularization reduce overfitting?

A common way to reduce overfitting in a machine learning algorithm is to use a regularization term that penalizes large weights (L2) or non-sparse weights (L1) etc. How can such regularization reduce overfitting, especially in a classification…
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Regularisation: why multiply by 1/2m?

In the week 3 lecture notes of Andrew Ng's Coursera Machine Learning class, a term is added to the cost function to implement regularisation: $$J^+(\theta) = J(\theta) + \frac{\lambda}{2m} \sum_{j=1}^n \theta_j^2$$ The lecture notes say: We could…
Tom Hale
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why regularization is slower slope and not higher?

I am reading about regularization in Aurelien Geron's book. I do understand that given a model $\beta_0$+ $x$ $\beta_1$ , regularization means: If we allow the algorithm to modify $\beta_1$ but we force it to keep it small, then the learning…
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How to prove this regularized matrix is invertible?

So I'm taking Andrew Ng's course on machine learning (great course, only comment is that its lacking a lot of math) and we came across the analytical solution to a model using Normal equations with the regularization penalty. Andrew claims that it…
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Why is regularization used only in training but not in testing?

From the book Hands-On Machine Learning: Note that the regularization term should only be added to the cost function during training. Once the model is trained, you want to use the unregularized performance measure to evaluate the model’s…
nnp
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L1 and L2 penalty vs L1 and L2 norms

I understand the usages of L1 and L2 norms however I am unsure of usage of L1 and L2 penalty when building models. From what I understand: L1: Laplace Prior L2: Gaussian Prior are two of the penalty terms. I have tried to read about these but there…
power.puffed
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What is the main reason why the cost function is smoother with L2 regularization?

Why does L2 regularization smooth the loss surface? went over my head.
alwayscurious
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What regularizer to use for small datasets?

If I have a sparse dataset with very few points, which regularization scheme should I use? That is, I have a dataset with only 10 points. Are there regularizers that would help me in this situation?
echo
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Does decreasing regularisation parameter always decrease loss

For a training problem with some loss function $L(w) = \frac{1}{N}\sum_{i=1}^N l(w, x_i, y_i) + \lambda ||w||^2_2$, where $l(w, x_i, y_i)$ is something like least squares and the global minimum of $L(w)$ can always be found, how can I show that…
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What's the relationship between the regularization parameter lambda and the constrain parameter K

In regularized regression, for example the ridge regression, we have the Lagrange method, which adds lambda times the 2-norm of parameters to the loss function and minimizes this. On the other hand, this is equivalent to minimizing the loss function…
kaixu
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L1 L2 regularization

The tutorial says the intersection point for L1 and L2 regularization gives the minimum loss - But why the intersection gives the minimum loss? I cannot interpret the graph clearly.
william007
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Regularization in Statistics and Machine Learning

Reading the Scikit-learn docs on logistic regression (https://scikit-learn.org/stable/modules/linear_model.html#logistic-regression), I came across this note: Note: Regularization is applied by default, which is common in machine learning but not…
Enk9456
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Regularization strength and problem size

Let's say I run an Ordinary Least Square regression with a Ridge regression on 100.000 points randomly sampled from a huge dataset. The best regularization strength found is C=1. What is approximately the optimal regularization strength I can expect…
mbl
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