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At a nuclear plant great care is taken to measure the employees health.These are the number of visits made by each of the 10 employees to the doctor during a calender year. 3,6,5,7,4,2,3,5,1,4

Assuming the number of visits made by employee has a poisson distribution ,test the hypothesis that the annual mean per employee is greater than 3.

I am using the graphical method and I am not sure of which p[X=x] should i consider.

X: no.of visits by each employee to the doctor.

H0:lambda=3
H1:lambda>3
X follows a Poisson(3)

Then what is the probability that I should check?

What I did was as the average of sample data is 4.73636. Therfore calculated p[X>=4] and checked if it was in the critical region. Is this the correct probability to calculate? In a poisson distribution the expected value is calculated as x*p[X=x] right?Not as (sigma x*f(x))/(sigma x)

clarkson
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1 Answers1

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Clarkson - a convenient method for this particular problem will be to recognise that the sum of poisson variables is also poisson. In this case, you would model the total number of visits in the year as poisson(30) and see what you can infer from there.

  • Thanks.Then I should look for P[X>=40] right? As there is a total of 40 days.One question.Should my null hypothesis change into H0:lambda=30 or is it lamda=3 – clarkson Oct 28 '13 at 15:52
  • Yes, lambda = 30, so you average 3 vistits per year per employee. This will be a one sided test, you want to calculate the probability $P(X\geq 40)$ under the null. –  Oct 28 '13 at 16:03