If you roll 5 standard 6 sided dies, what's the probability that you will get at least three 2s?
I imagine it would be 1 - P(0 twos) - P(1 two) - P(2 twos), but I don't know how to calculate the probability of these.
If you roll 5 standard 6 sided dies, what's the probability that you will get at least three 2s?
I imagine it would be 1 - P(0 twos) - P(1 two) - P(2 twos), but I don't know how to calculate the probability of these.