I have samples from two random variables, and I'm assuming normal distribution with equal variance. I want to show that the distributions have equal means $\mu_1$ and $\mu_2$.
The usual two-tailed t-test is used with the inverse situation. That is, one constructs the following and hopes for a resulting $p$ small enough to reject H0.
- H0: the null hypothesis $\mu_1 = \mu_2$
- H1: the alternative hypothesis $\mu_1 \neq \mu_2$
But I want to reject H1, and show with statistical significance that H0 is true.
Can I use the same two-tailed t-test and just interpret the results differently? Or do I need an entirely different hypothesis test?
My first reaction was to use the same test, end up with a large $p$ instead of a small one, and then claim that H1 was rejected with confidence $1 - p$. But after messing around with some data, I'm not sure that's the right approach.
[tost]tag as this may be useful to future searchers.) – Silverfish Feb 01 '24 at 00:47