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I am having some trouble understanding the difference in use of the anova() function and summary() function. For context, here is what I am working on:

I am using GLMMs:

glmm_dogs2 <- lmer(Den.Weeks ~ Humans * Predators + (1|packseasid), data = dogs)

glmm_dogs3 <- lmer(Den.Distance ~ Humans * Predators + (1|packseasid), data = dogs)

glmm_dogs4 <- lmer(Pups.lost ~ Humans + Predators + Den.Distance + (1|packseasid), data = dogs)

The code that I based myself on then continues to plot the residuals and test for normality of residuals, and then goes on to the results, using both Anova(glmm_dogs2) and summary(glmm_dogs2). Then I get the following output:

Anova(glmm_dogs2) 
Analysis of Deviance Table (Type II Wald chisquare tests)
Response: Den.Weeks
              Chisq Df Pr(>Chisq)  
Humans           2.1423  1    0.14329  
Predators        5.5678  1    0.01829 *
Humans:Predators 5.0390  1    0.02478 *
-------------
summary(glmm_dogs2)
Linear mixed model fit by REML. t-tests use
  Satterthwaite's method [lmerModLmerTest]
Formula: 
Den.Weeks ~ Humans * Predators + (1 | packseasid)
   Data: dogs

REML criterion at convergence: 98.4

Scaled residuals: Min 1Q Median 3Q Max -1.5586 -0.4267 -0.0769 0.6049 1.6837

Random effects: Groups Name Variance Std.Dev. packseasid (Intercept) 1.015 1.008
Residual 2.012 1.419
Number of obs: 28, groups: packseasid, 11

Fixed effects: Estimate Std. Error df t value Pr(>|t|) (Intercept) 9.9312 0.4444 14.2747 22.347 1.64e-12 *** Humans1 -2.3783 0.9541 20.1319 -2.493 0.02151 * Predators1 -3.6509 1.1213 18.7048 -3.256 0.00422 ** Humans1:Predators1 3.9813 1.7736 21.8223 2.245 0.03526 *


Signif. codes:
0 ‘*’ 0.001 ‘’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Correlation of Fixed Effects: (Intr) Humns1 Prdtr1 Humans1 -0.255
Predators1 -0.179 0.126
Hmns1:Prdt1 0.099 -0.579 -0.673

Now I have Chisq and Pr(>Chisq) values, and I have t and Pr(>|t|) values. According to the Anova(), the interaction between Humans:Predators is significant, and Predators is significant, while according to the summary(), all terms including the interaction are significant. [Side-note: I already used the dredge(global_glmm) function to compace AIC's, so my model has already been reduced, this question mainly pertains to how I should report my results and which variables I can consider to be significantly related to eachother.]

I did read that the Anova() does a Type II test, and summary() does a type III test, so if I understood it correctly, this means that in this case I should use the summary() output, because of the significant interaction Humans:Predators. However, if the summary() function gave me no significant result, I should use the Anova() results? Or did I misinterpret this?

FYI, below are the results of one of the other GLMM's I constructed, where there is no significant interaction; in this case I would then use the Anova() results in my report because the summary() didn't show any significant interactions?

Anova(glmm_dogs3)
Analysis of Deviance Table (Type II Wald chisquare tests)
Response: Den.Distance
          Chisq Df Pr(>Chisq)  
Humans           3.4109  1    0.06477 .
Predators        0.0976  1    0.75467  
Humans:Predators 1.3987  1    0.23694  
---
Signif. codes:  
0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

> summary(glmm_dogs3) Linear mixed model fit by REML. t-tests use Satterthwaite's method [lmerModLmerTest] Formula: Den.Distance ~ Humans * Predators + (1 | packseasid) Data: dogs

REML criterion at convergence: 108.9

Scaled residuals: Min 1Q Median 3Q Max -1.28514 -0.50117 -0.01259 0.56893 2.10258

Random effects: Groups Name Variance Std.Dev. packseasid (Intercept) 2.554 1.598
Residual 2.652 1.628
Number of obs: 28, groups: packseasid, 11

Fixed effects: Estimate Std. Error df t value Pr(>|t|) (Intercept) 2.1269 0.6105 11.2745 3.484 0.00494 ** Humans1 0.9035 1.1232 17.1159 0.804 0.43221
Predators1 -0.7322 1.3067 15.6333 -0.560 0.58319 Humans1:Predators1 2.4991 2.1131 18.7481 1.183 0.25172


Signif. codes:
0 ‘*’ 0.001 ‘’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Correlation of Fixed Effects: (Intr) Humns1 Prdtr1 Humans1 -0.211
Predators1 -0.143 0.132
Hmns1:Prdt1 0.071 -0.586 -0.670

  • Which type of sum of squares you should use depends on what you want to find out. See https://stats.stackexchange.com/questions/20452/how-to-interpret-type-i-type-ii-and-type-iii-anova-and-manova – Peter Flom Jan 21 '24 at 11:49

0 Answers0