Let $X \sim Beta(a,b)$. I was wondering what is the distribution of $\frac{1}{X}$?. Here is my derivation by using transformation of random variable.
Let $Y = h (X) = \frac{1}{X}$, which implies $h^{-1} (y) = 1/y$ and $h^{'-1} (y) = -1/y^2$
\begin{align} f_Y (y) &= f_X( h^{-1} (y) ) \left|\frac{d}{dy} h^{-1} (y)\right|\\ &= \frac{1}{B(a,b)} (1/y)^{a-1} (1-1/y)^{b-1} \left|-1/y^2 \right| \\ &= \frac{1}{B(a,b)} (1/y)^{a+2-1} (1-1/y)^{b-1} \\ &= \frac{B(a+2,b)}{B(a,b)} \ \frac{1}{B(a+2,b)}(1/y)^{a+2-1} (1-1/y)^{b-1} \\ &\propto \frac{1}{B(a+2,b)}(1/y)^{a+2-1} (1-1/y)^{b-1} \end{align}
Very likely I am wrong on it. But just wondering if I can saying it is still beta distributed? I would appreciate it if someone could pointing out where I am getting wrong. Thanks a lot.