Let $X_1,X_2,\ldots$ be an infinite list of independent normal variables $X_i\sim\mathcal N(0,1)$, for $i=0,1,\dots$. Consider the the sum $$Y=\sum_ir^iX_i^2,$$ where $r\in(0,1)$ is a parameter to weight (geometrically) each term in the sum. By definition, for each random variable, we have $E[X_i^2]=1$. It's straightforward to see that: $$E[Y]=\sum_ir^iE[X_i^2]=(1-r)^{-1}.$$
I can also compute the variance of $Y$. We have $E[X_i^2X_j^2]=1$ if $i\neq j$ and $E[X_i^4]=3$: \begin{align} E[Y^2]&=\sum_{i\neq j}r^ir^j+3\sum_ir_i^2\\ &=\sum_{i,j}r^ir^j+2\sum_ir_i^2\\ &=(1-r)^{-2}+2(1-r^2)^{-1}. \end{align}
Using $\mathrm{Var}[Y]=E[Y^2]-E[Y]^2$, we find: $$\mathrm{Var}[Y]=2(1-r^2)^{-1}.$$
I am interested here to compute the explicit distribution of $Y$. According to the article on the chi-squared distribution in Wikipedia, there is no closed form for the (finite) sum of a linear combination of $\chi^2$ distributions.
However, I can make the assumption that $Y\sim a\chi^2(k)$ (or is at least close to) for a given $a$ and $k$ that I need to determine in some way. In practice, $r$ is close to $1$ so this assumption might be good enough for my purpose. Using basic properties of the $\chi^2$ distribution, I write the expectation as $E[Y]=ak$ and the variance as $\mathrm{Var}[Y]=2a^2k$.
Matching the first two moments of my real distribution and the $\chi^2$ approximation, I get: $$a=\frac1{1+r}\simeq\frac12$$ and: $$k=\frac{1+r}{1-r}\simeq\frac2{1-r},$$ which is likely a large value if $r$ is close to 1.
Does this type of approximation work in practice? If so, for which values of $r$ should I consider it safe? I am a bit concerned I get a factor of $2$ in the answers, I will need to check numerically if there is a mistake in my calculation.