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Assume we have matrices $A_{n\times n}$ and $\Delta_{n\times n}$ and know that:

$$A^{-1}_{i.}\Delta_{.j}\sim N(0,\,A^{-1}_{i.}\,\Sigma_j\,[A^{-1}_{i.}]^\top)\,,$$

where $\Delta\sim N(0,\,\Sigma_j)$, $i$ shows the rows and $j$ the columns; $_{i\,.}$ means row $i$ (vector with dimension $1\times n$) and $_{.\,j}$ means column $j$ (vector with dimension $n\times 1$). Note that this is the distribution of each pair in the $A^{-1}\Delta$ matrix.

Can we derive the distribution of $(A^{-1}_{i.}\Delta_{.j})^2=A^{-1}_{i.}\Delta\,A^{-1}\Delta_{.j}$? Is it a $\chi^2$? If so, what are the parameters?

statwoman
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  • @User1865345 I have added some clarifying points. I believe in the general sense, yes, as it is just the square of a normal distribution, but I don't know what the parameters would be. – statwoman Mar 16 '23 at 21:50
  • https://stats.stackexchange.com/questions/93383/square-of-normal-distribution-with-specific-variance is the solution you are looking for – Onyambu Mar 17 '23 at 03:03

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