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If weighted precision is calculated as

weighted_precision = [(pc1*c1)+(pc2*c2)]/(c1+c2)

where, pc1 = precision of class 1 c1 = no.of samples in class 1 pc2 - precision of class 2 c2 = no.of samples in class 2

How does the above equation change while dealing with class imbalance via

  • Class Weights
  • Oversampling
  • Kaushik J
    • 101
    • 3

    0 Answers0