The following multivariate distribution is given:
$\left(\begin{array}{c}X_1 \\ X_2 \\ X_3\end{array}\right) \sim N_3\left(\left(\begin{array}{c}1 \\ 1 \\ 1\end{array}\right),\left(\begin{array}{ccc}1 & 0 & -1\\ 0 & 3 & 0\\ -1 & 0 & 2\end{array}\right)\right)$
The goal here is to derive the conditional distribution of $X_3$ given $X_1=X_2=0$. This is difficult for me, because I do not know yet how to deal with two conditions. From what I found online is that:
The conditional distribution of $\mathbf{X}_1$ given known values for $\mathbf{X}_2=\mathbf{x}_2$ is a multivariate normal with:
\begin{align} \text{mean vector} & = \mathbf{\mu_1 + \Sigma_{12}\Sigma_{22}^{-1}(x_2-\mu_2)}\\ \end{align}
\begin{align} \text{covariance matrix} & = \mathbf{\Sigma_{11} - \Sigma_{12}\Sigma_{22}^{-1}\Sigma_{21}} \end{align}
The problem is that the formula is given for only one condition, but my exercise has two conditions.
Could I please get feedback on this?
Tim