ksh scripting, For loop

Question

#!/bin/ksh
#########################     
for i in {1..30} ;do
  echo $i
done

output is:

{1..30}

What is wrong in my code?

Possible duplicate of [for loop range not working ksh](http://stackoverflow.com/questions/3005265/for-loop-range-not-working-ksh) — ceving, Nov 25 '16 at 15:32

kev · Accepted Answer · 2012-04-02T13:44:34.177

6

{1..30} belongs to bash.

Use this:

for((i=1;i<=30;i++)); do
    echo $i
done

edited Apr 02 '12 at 13:44

answered Apr 02 '12 at 13:38

kev

+1. I hadn't thought that the Korn Shell supported arithmetic for-loops, but [apparently it does](http://docstore.mik.ua/orelly/unix3/korn/ch06_03.htm)! – ruakh Apr 02 '12 at 13:47
1

`for(())` was supported since `Ksh93`. – kev Apr 02 '12 at 13:54
too bad it's not supported in mksh – Sergiy Kolodyazhnyy Apr 27 '15 at 20:49

score 3 · Answer 2 · answered Jan 02 '13 at 08:38

3

Alternatively you can switch to a while construction:

i=1
while (( i <= 30 ))
do
   echo $i
   (( i+=1 ))
done

answered Jan 02 '13 at 08:38

score 0 · Answer 3 · answered Jun 30 '15 at 14:35

0

 for {set x 0} {$x<10} {incr x} {
             puts "x is $x"
           }

answered Jun 30 '15 at 14:35

Dbase Cos

3 Answers3