Simple Concatenation in C

Question

I'm not good in C, top of that I'm doing after very long, I need to do a very simple thing:

char code[]="aasd";
char *rmessage="";
strcat(rmessage,code[0]);

I simply want to concatenate the content of index 0 of array code to rmessage.

The two declarations are not the same. This [link](http://stackoverflow.com/questions/3862842/difference-between-char-str-string-and-char-str-string) may help you. — Sunmit Girme, Mar 21 '12 at 09:03

score 4 · Answer 1 · answered Mar 21 '12 at 08:34

You need to ensure there is enough space in rmessage to store the result of the concatentation. You can use strncat to specify the number of characters to copy from a string:

char code[] = "aasd";
char rmessage[1024] = "";

strncat(rmessage, code, 1);

or, in this case, just assign the first character of rmessage:

rmessage[0] = code[0];

score 1 · Answer 2 · answered Mar 21 '12 at 09:32

Not coding in C for long time.I think the syntax is just correct.

int sz=10; // sz = # number of chars you want to store + 1 , i assumed 9 characters will be stored at max. 
char code[] = "aasd";
char *rmessage = malloc(sz*sizeof(char));
rmessage[0]=code[0];
rmessage[1]=NULL;

*Remember to deallocate the memory allocated to rmessage after your job is done.

free(rmessage);

Simple Concatenation in C

2 Answers2