Regex to handle images

Question

How do I replace with text:

<img src="anyurl">

with:

<some extra html><img src="anyurl" alt=""></someextrahtml>

What is right regex to handle <img src="*">?

Does this really *have* to be regex? Couldn't you use an HTML parser instead? — Mark Byers, Mar 20 '12 at 12:38
possible duplicate of [Grabbing the href attribute of an A element](http://stackoverflow.com/questions/3820666/grabbing-the-href-attribute-of-an-a-element) — soulmerge, Mar 20 '12 at 12:38

score 2 · Answer 1 · answered Mar 20 '12 at 12:41

2

try this /(<img.+src="[^"]"[^>]>)/si but regex is not the preferred way to handle this. You should use DomDocument

answered Mar 20 '12 at 12:41

Rob

how do I throw src of the image to separate variable? – Jasper Mar 20 '12 at 12:46
You need to create a backreference with () so `/]>/si` – Rob Mar 20 '12 at 12:49
`preg_match('/]>/si', $html, $matches);` – Rob Mar 20 '12 at 13:14
foreach $matches as $match = each src? – Jasper Mar 20 '12 at 13:15
Better to use a DOM Document if you're working with a DOM, but perhaps not if you're working with a fragment e.g. a comment etc. – Paul Bain Mar 20 '12 at 13:35

score 1 · Accepted Answer · edited Mar 18 '14 at 21:56

1

Try this regex:

/<img\s+src="(.*?)"\s+\/?>/

It'll grap the source of images.

EDIT

Here it is in PHP!

preg_match('/<img\s+src="(.*?)"\s+\/?>/', $target, $matches);
var_dump($matches);

So your src should be in $matches[0];

edited Mar 18 '14 at 21:56

HamZa

answered Mar 20 '12 at 12:39

Paul Bain

2 Answers2