do loop printing two printf statements together

Question

Possible Duplicate:
C: function skips user input in code

#include <stdio.h>

int main (int argc, const char * argv[])
{
char item;
int row;
int size;
int price_list[5][8] =
{
    {9,18,27,36,45,54,63,72},
    {10,20,30,40,50,60,70,80},
    {11,22,33,44,55,66,77,88},
    {12,24,36,48,60,72,84,96},
    {13,26,39,52,65,78,91,104}
};
do {
printf("Please enter the item:\n");

scanf("%c", &item);

printf("Please enter the size:\n");
scanf("%d", &size);
    switch (item) {
    case 'e':
        row = 0;         
        break;
    case 't':
        row = 1;
        break;
    case 's':
        row = 2;
        break;
    case 'u':
        row = 3;
        break;
    case 'd':
        row = 4;
        break;
    default:
            row = 5;
        break;
}
    if (row < 5) {
        printf("%d\n", price_list[row][size]);
    }
}
while (item != 'q');


return 0;
}

the loop runs properly for the first time and then it prints the two printf statements at once like Please enter the item: e Please enter the size: 1 18 Please enter the item: Please enter the size:

Why does this happen?