How to read the url from request

Question

I want to read a request url using spring ,i have method like below and the client request url is like http://localhost:8080/api/getName ,i want to read (/api/getName from this url)

@Controller
public class TestController  {

    @RequestMapping(value = "/", method = RequestMethod.GET)
    public ResponseEntity<String> getDetails(
            final HttpServletRequest request,
            final HttpServletResponse response) throws Exception {

        }

Why? Are you going to put your own dispatch mechanism on top of the one already in Spring? — Dave Newton, Feb 21 '12 at 17:05

score 1 · Answer 1 · edited May 23 '17 at 12:03

1

It's a method in HttpServletRequest: request.getRequestURL() gives you the URL.

See this answer for some more details: How to get the request url from HttpServletRequest

To further analyse the URL, use it's methods: Parsing a URL

edited May 23 '17 at 12:03

Community

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answered Feb 21 '12 at 17:05

Aaron Digulla

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is there any way just to read '/api/getName' from the entire url that is http://localhost:8080/api/getName ? – user1195292 Feb 21 '12 at 18:10
Use `getPath()` on the URL: http://docs.oracle.com/javase/tutorial/networking/urls/urlInfo.html – Aaron Digulla Feb 22 '12 at 08:04
@user1195292: the method getRequestURI() returns exactly what you are asking for. See API Doc linked in my answer. – Tomas Narros Feb 22 '12 at 10:46

score 0 · Answer 2 · answered Feb 21 '12 at 17:06

0

req.getContextPath();

Should get you the context path you are looking for.

answered Feb 21 '12 at 17:06

ring bearer

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score 0 · Answer 3 · answered Feb 21 '12 at 17:07

0

You might also want to browse the api javadocs

http://docs.oracle.com/javaee/6/api/javax/servlet/http/HttpServletRequest.html

answered Feb 21 '12 at 17:07

bluesman

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Tomas Narros · Answer 4 · 2012-02-21T17:19:40.487

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i want to read (/api/getName from this url)

For this you can use the HttpServletRequest method getRequestURI(). It will return the request URL, without the protocol/server/port part, and without the query String (the parameters).

edited Feb 21 '12 at 17:19

answered Feb 21 '12 at 17:12

Tomas Narros

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How to read the url from request

4 Answers4