How to test if $value is $num +-3

Question

Possible Duplicate:
php if integer between a range?

Let's say $num = 5; How do I test if $value is anything in between +-3 of $num. In other words, how can I test if $value is equal to any of these values 2,3,4 5 6,7,8

Answer 1

Two possible ways to do it:

1. $num - 3 <= $value && value <= $num + 3
2. abs($num - $value) <= 3

Answer 2

$mid = 5;
$range = 3;
$inRange = ($myval>=$mid-$range && $myval<=$mid+$range) ? TRUE : FALSE;

UPDATE I started throwin' out bass, she started throwin' back mid-range.

Answer 3

if ($num - 3 <= $value && $value <= $num + 3)

Answer 4

if ($value<=$num+3 && $value>=$num-3)
    echo "$value is between +-3 of $num";
else
    echo "$value is outside +-3 of $num";

Answer 5

try this:

$dif1 = $num - 3;
$dif2 = $num + 3;

if($dif1 <= $value){
       if($dif2 <= $value){
              echo "Your number in between +-3";
       }  
}

Answer 6

There is nothing big logic in this if you know the $num value take two variable $min and $max

set $min = $num - 3

set $max = $num + 3

and then with condition check your value..

$value > $min && $value < $max