calling a jQuery function named in a variable

Question

I have several jQuery function like function setOne(); setTwo(); setThree();

and a variable var number that values respectively "one", "two", "three".

How can I call function "setOne()" when number values "one", function "setTwo" when number values "two" and so on...?

Thank you so much in advance. Any help will be apreciated.

Looks like normal JavaScript functions to me. – Felix Kling Dec 21 '11 at 10:28 — Felix Kling, Dec 21 '11 at 10:28

Andreas Louv · Accepted Answer · 2016-12-01T18:59:41.447

45

If you have your function in the global scope (on the window object) you can do:

// calls function setOne, setTwo, ... depending on number.
window["set" + number]();

And using eval will allow you to run functions in local scope:

eval("set" + number + "()");

When is JavaScript's eval() not evil?

edited Dec 01 '16 at 18:59

answered Dec 21 '11 at 10:31

Andreas Louv

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Best answer, I accept this, simple and helpful and you know exactly what I mean! Thank you! If you you want you can vote my question. – bobighorus Dec 21 '11 at 10:39
`this["set" + number]();` would not work. Only if `setX` is a property of whatever `this` refers to, but not if `setX` is a local variable. – Felix Kling Dec 21 '11 at 10:43
1

Sorry, but if `number` is exactly as bobighorus describes (e.g. `one`, `two`, `three`) then this will give an error, as `setone` != `setOne`?! – Yoshi Dec 21 '11 at 10:55
@AndreasAL Ah, thanks! ;) Then why not copy that part from my answer so we'll have it in the accepted answer too :) – Yoshi Dec 21 '11 at 11:02
Great ! Congratulations – w3spi Nov 29 '21 at 07:31

score 8 · Answer 2 · answered Dec 21 '11 at 10:27

8

Create a name -> function map:

var funcs = {
    'one': setOne,
    'two': setTwo
    /*...*/
};

Then you call the function with:

funcs[number]();

answered Dec 21 '11 at 10:27

Felix Kling

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Actually AndreasAL's answer is the better one. People need to understand that in JavaScript everything is a dictionary and even functions are only entries on the global scope dictionary that you can access in that way. – Tigraine Dec 21 '11 at 10:33
Thanks for your answer Felix, but it seems like a switch iteration. I need an automatic solution like set+number+() that means setOne(); . I hope I was clear. – bobighorus Dec 21 '11 at 10:34
@Tigraine: It only works if the functions are global which in general is not a good idea (global namespace pollution). – Felix Kling Dec 21 '11 at 10:37
@bobighorus: Well, you can also assign the functions directly to the object instead of defining them beforehand. Whether you do `function setOne() {...};` or `funcs['one'] = function() {...};` should not make a big difference. The advantage is that your code has a cleaner structure and is easier to understand. – Felix Kling Dec 21 '11 at 10:39
@Felix Kling: You can still declare the functions on a deeper scope and use the this[] notation as AndreasAL suggested.. – Tigraine Dec 21 '11 at 10:41
@Tigraine: That won't work. Only in global scope `this` refers to `window`, but you can never access local variables through `this`. – Felix Kling Dec 21 '11 at 10:42
@Felix Kling: You can simply do so by setting this through `.call` but you get into trouble as `function ()` are only seen as local variables inside functions.. Best I could come up is similar to your approach: http://jsfiddle.net/85YSX/ – Tigraine Dec 21 '11 at 10:58

Hozeis · Answer 3 · 2016-03-15T14:23:36.470

7

If the variable details the actual name of the JQuery function and you want to apply the function to a DOM element like 'body', you can do the following:

 $('body')['function-name']('params');

edited Mar 15 '16 at 14:23

answered Sep 30 '15 at 11:58

Hozeis

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score 2 · Answer 4 · answered Dec 21 '11 at 10:32

Provided your functions are in the global scope, try:

function setOne() {
  console.log('setOne called');
}
function setTwo() {
  console.log('setTwo called');
}
function setThree() {
  console.log('setThree called');
}

var number, funcName;

number = 'one';
funcName = 'set' + number.charAt(0).toUpperCase() + number.slice(1);
window[funcName](); // output: setOne called

number = 'two';
funcName = 'set' + number.charAt(0).toUpperCase() + number.slice(1);
window[funcName](); // output: setTwo called

number = 'three';
funcName = 'set' + number.charAt(0).toUpperCase() + number.slice(1);
window[funcName](); // output: setThree called

score 1 · Answer 5 · answered Dec 21 '11 at 10:34

1

As simple as this is:

function hello(){
    alert("hello");
}
var str = "hello";
eval(str+"()");

answered Dec 21 '11 at 10:34

I.G. Pascual

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Yeah but I have to call a function! – bobighorus Dec 21 '11 at 10:40
1

@bobighorus This calls the function hello()... use `var str = "One";` `eval("set" + str + "()");` for your example. You can even set *named parameters* this way... `eval("set" + str + "(parameterName)");` – I.G. Pascual Dec 21 '11 at 10:52

score 0 · Answer 6 · answered Dec 21 '11 at 10:30

0

Why do you have three functions for that?

var number;
function setNumber(n) {
    number = n;
}

setNumber(1) will set number to 1

setNumber(2) will set number to 2

ect

answered Dec 21 '11 at 10:30

OptimusCrime

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Thanks for yuou answer, but I think that you don't understand my question...:) – bobighorus Dec 21 '11 at 10:40

calling a jQuery function named in a variable

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