Expression for "is x greater than y and less than z"?

Question

I'm trying to test if a number is greater than 0 but less than 8. How do I do that in JavaScript?

This is what I'm trying:

if (score > 0 < 8) { alert(score); }

@tom Simple. `score>>>0` converts `score` to a non-negative integer. (Negatives become very large positive values due to two's complement representation.) If it is 8 or larger, `min` produces 8, bitwise and'ed with 7 to 0, a falsy value. If it is between 0 and 7, `min` changes nothing and neither does `&`, resulting in a falsy value of 0 or a truthy value between 1 and 7. — ephemient, May 01 '19 at 19:25
@AlexejMagura Chained inequality notation has been in use in mathematics for centuries. How's that for tradition? (e.g., Paolo Ruffini's General Theory of Equations, 1799, p. 82) — Magnus Lind Oxlund, Apr 03 '20 at 17:33
A related question: https://stackoverflow.com/q/6967573/1662230 — Magnus Lind Oxlund, Apr 04 '20 at 15:58
A tangential question: https://stackoverflow.com/q/4090845/1662230 — Magnus Lind Oxlund, Apr 04 '20 at 16:12

score 46 · Accepted Answer · answered Nov 23 '11 at 03:07

46

Here's the code:

if (score > 0 && score < 8){
    alert(score);
}

P.S. This has nothing to do with jQuery. It's simple, naked JavaScript!

answered Nov 23 '11 at 03:07

Joseph Silber

So strange. I know that's how one uses multiple conditions (whereby of course both conditions must be true), but it's not working in my code :( I've never had this not work before... – oldboy May 27 '17 at 21:46

score 2 · Answer 2 · answered Nov 23 '11 at 03:07

2

if ((score > 0) && (score < 8)) {
    alert(score);
}

But this is JavaScript, not jQuery.

answered Nov 23 '11 at 03:07

Dave Newton

score -1 · Answer 3 · answered Nov 23 '11 at 03:09

-1

Try:

if(score > 0 && score < 8){alert(score);)

answered Nov 23 '11 at 03:09

Alex Peattie

The comparison is more meaningful, but the syntax error is still present. – Magnus Lind Oxlund Apr 04 '20 at 20:50

3 Answers3