C++: right justified field ouput

Question

I wanna output a matrix in right-justified fields of length 8 in C++.
Is there any facility to make that easy to code?

don't use the C tag unless you are asking a C question / don't write C/C++ in the title if your question is about C++ — Sebastian Mach, Nov 14 '11 at 15:16

kbyrd · Accepted Answer · 2011-11-14T15:26:37.230

5

You can use std::right and std::setw to get right justified fields in iostream. The default padding char is space, but you can change it with setfill(). Also, right isn't strictly necessary as I believe it is the default, but it's nice to be explicit.

std::cout << std::right << std::setw(8) << data_var

edited Nov 14 '11 at 15:26

answered Nov 14 '11 at 15:09

kbyrd

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Please don't encourage the use of `std::endl` when `'\n'` is more appropriate. See [`endl` fiasco](http://stackoverflow.com/questions/5492380/what-is-the-c-iostream-endl-fiasco/5492605#5492605). – Robᵩ Nov 14 '11 at 15:20

score 1 · Answer 2 · answered Nov 14 '11 at 15:07

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Perhaps printf("%-8d", 1234); ?

answered Nov 14 '11 at 15:07

Basile Starynkevitch

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No. It left justifies the number. – a-z Nov 14 '11 at 15:13
Then try `printf("%+8d", 1234);` ? – Basile Starynkevitch Nov 14 '11 at 15:15
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If the question had been tagged C I would have done +1. But its not. – Martin York Nov 14 '11 at 15:52

score 1 · Answer 3 · answered Nov 14 '11 at 15:10

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Yes

 std::right

will right justify and

std::setw(8)

will set the field width to 8.

answered Nov 14 '11 at 15:10

Grammin

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C++: right justified field ouput

3 Answers3