Remove contents of href attribute with with RegEx

Question

For example, I have this HTML snippet:

<a href="/sites/all/themes/code.php">some text</a>

The question is - how to cut the text /sites/all/themes/code.php from the href with preg_replace(); which pattern could I use?

Possible Dupe: http://stackoverflow.com/questions/2792900/regex-javascript-to-match-href — chown, Oct 01 '11 at 19:13

score 3 · Answer 1 · answered Oct 01 '11 at 18:38

3

I would strongly recommend against using regular expressions to parse any SGML derivative.

For HTML use some DOM parser. For PHP specifically there is DOMDocument.

answered Oct 01 '11 at 18:38

Alexander Olsson

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score 0 · Accepted Answer · answered Oct 01 '11 at 19:09

0

pattern:

(<a .*?href=")([^"]*)

replacement: $1

answered Oct 01 '11 at 19:09

Alexey

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score 0 · Answer 3 · answered Oct 01 '11 at 21:10

you don't have to do a "replace"

(?<=<a href=")[^"]*(?=">)

brings you what you want directly.

test with grep:

kent$  echo '<a href="/sites/all/themes/code.php">some text</a>'|grep -oP '(?<=<a href=")[^"]*(?=">)'                                    
/sites/all/themes/code.php

Remove contents of href attribute with with RegEx

3 Answers3