How do I initialize the mutex locks and condition variables

Question

pthread_mutex_t qlock[5] = PTHREAD_MUTEX_INITIALIZER;

pthread_cond_t qcond[5] = PTHREAD_COND_INITIALIZER;

It is giving me error as follows...

error: array must be initialized with a brace-enclosed initializer

.. Please, can somebody debug this or tell me a way to solve it...

You have asked 14 questions and accepted no answers! It's impossible you did not get a single decent answer to all these questions - please go over your questions and acknowledge the time and effort other people have put in answering them! — Branko Dimitrijevic, Oct 01 '11 at 17:41
@Invictus See the [faq](http://stackoverflow.com/faq#howtoask) but the short version is click on the check box next to the answer that best answers your question. — Ze Blob, Oct 01 '11 at 18:57

score 3 · Accepted Answer · answered Oct 01 '11 at 17:11

3

This initializes a mutex:

pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;

This initializes an array:

int array[5] = { 0, 1, 2, 3,  4 };

...that should be enough to get you going.

answered Oct 01 '11 at 17:11

K-ballo

We can do for the mutex lock, but, what about condition variable?? – Invictus Oct 01 '11 at 17:27

score 1 · Answer 2 · edited May 23 '17 at 12:14

1

I'd suggest you reading a beginner book on C programming language. See for example a related SO question.

BTW, at this level of C knowledge I would highly recommend you to stay away from multithreaded programming (at least with pthreads).

edited May 23 '17 at 12:14

Community

answered Oct 01 '11 at 17:22

Ilia K.

2 Answers2