Drawable resource using a variable

Question

I want to use a variable instead of R.drawable.myimage because I have a database with the image's names. I get the name from the database and I want to use the drawable resource with this name.

String flagimage = "R.drawable." + myHelper.getFlagImage(5);
int resourceId = Integer.parseInt(flagimage);
Bitmap flag = BitmapFactory.decodeResource(getResources(), resourceId);

score 40 · Accepted Answer · edited Sep 07 '16 at 08:42

40

You can use the name of a resource like

getIdentifier (String name, String defType, String defPackage);

getResources().getIdentifier("us","drawable","com.app");

The above function will return an integer value same as R.drawable.us.

This is how you access with resource names.

edited Sep 07 '16 at 08:42

Nikunj Paradva

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answered Sep 25 '11 at 08:02

blessanm86

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Just a quick note [getIdentifier](http://developer.android.com/reference/android/content/res/Resources.html#getIdentifier%28java.lang.String,%20java.lang.String,%20java.lang.String%29) returns `0` if no such resource was found. (0 is not a valid resource ID.) – razz Feb 07 '16 at 05:44

score 18 · Answer 2 · answered Sep 25 '11 at 08:04

18

You can use this code to get the identifier...

 Resources res = this.getResources(); 
 int resID = res.getIdentifier(imagename, "drawable", this.getPackageName());

answered Sep 25 '11 at 08:04

mAndroid

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After alot of search it worksss greattt work . Thanks – Ahmad Arslan Apr 24 '14 at 11:13

Drawable resource using a variable

2 Answers2

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