Converting CSV to array

Question

I have this array with airport codes and city names (around 3500 lines).

code,city
"Abilene, TX ",ABI
"Adak Island, AK ",ADK
"Akiachak, AK ",KKI
"Akiak, AK ",AKI
"Akron/Canton, OH ",CAK
"Akuton, AK ",KQA
"Alakanuk, AK ",AUK
"Alamogordo, NM ",ALM

I need to convert that file into a php array. This is my code so far:

if(($handle = fopen('test.csv', 'r')) !== FALSE) {
    while (($data = fgetcsv($handle, 1000, ',', '"')) !== FALSE) {
        echo '<pre>';
            print_r($data);
            echo '</pre>';
    }
    fclose($handle);
}

Although I'm setting the delimiter and enclousure characters for the fgetcsv function, im getting this as a result:

Array
(
    [0] => code
    [1] => city
"Abilene
    [2] => TX "
    [3] => ABI
"Adak Island
    [4] => AK "
    [5] => ADK
"Akiachak
    [6] => AK "
    [7] => KKI
"Akiak
    [8] => AK "
    [9] => AKI
"Akron/Canton
    [10] => OH "
    [11] => CAK
"Akuton
    [12] => AK "
    [13] => KQA
"Alakanuk
    [14] => AK "
    [15] => AUK
"Alamogordo
    [16] => NM "
    [17] => ALM
)

Are you sure those are `"` chars and not the fancy 66's and 99's that MS loves to sprinkle everywhere? — Marc B, Sep 21 '11 at 15:27
Works fine for me. Probably a bug in your `PHP_VERSION`. (Which is it?) Alternatively try `var_dump(array_map("str_getcsv", file($fn)))`. — mario, Sep 21 '11 at 15:28
@StefanPantke: Now that you mention it. He gets exactly one record out of it. So it's the line breaks which are not recognized, therefore the quotes being misinterpreted as well. — mario, Sep 21 '11 at 15:34
@StefanPantke: The `1` is just the result of `print_r()` which gets written out by the `echo` *after* print_r itself already threw its output out. (Why it's also not within the pre tags.) — mario, Sep 21 '11 at 17:34
@StefanPantke i fixed the output, still that is not the issue. I think Mario kind of has a point with the line breaks though. — Andres SK, Sep 21 '11 at 19:38
Possible duplicate of [How to create an array from a CSV file using PHP and the fgetcsv function](https://stackoverflow.com/questions/1269562/how-to-create-an-array-from-a-csv-file-using-php-and-the-fgetcsv-function) — Ali Hesari, Sep 21 '17 at 19:11

score 20 · Accepted Answer · answered Sep 21 '11 at 19:42

20

If it's the linebreaks, you can try the brute-force method with:

$file = file_get_contents("test.csv");
$data = array_map("str_getcsv", preg_split('/\r*\n+|\r+/', $file));
print_r($data);

str_getcsv is available with PHP 5.3, or as workaround in the manual, via upgradephp or PHP_Compat.

answered Sep 21 '11 at 19:42

mario

141,508
20
234
284

Excellent this fixed my issue. Thanks a lot – Raj Dec 16 '14 at 09:20
Great thank you +1 also for the unknown upgradephp!! – Magico Nov 05 '15 at 16:41

score 3 · Answer 2 · answered Dec 13 '14 at 06:38

Try this:-

ini_set('auto_detect_line_endings', TRUE);/// (PHP's detection of line endings) write at the top.


$csvrows = array_map('str_getcsv', file($filepath));
$csvheader = array_shift($csvrows);
$csv = array();
foreach ($csvrows as $row) {
   $csv[] = array_combine($csvheader, $row);
}

score 1 · Answer 3 · edited Aug 16 '17 at 18:32

1

try-

$csv = array();

if (($file = fopen('test.csv', 'r')) === false) {
    throw new Exception('There was an error loading the CSV file.');
} else {  
   while (($line = fgetcsv($file, 1000)) !== false) {
      $csv[] = $line;
   }
   fclose($handle);
}

edited Aug 16 '17 at 18:32

Don

3,811
13
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answered Dec 23 '14 at 06:44

Rekha

41
5

Converting CSV to array

3 Answers3

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