Fraction approximation to the nearest

Question

I have double number and i want to approximate it always to the nearest .

for eg: 1.2324 -> 1 1.898 -> 2

how can i do this with C#?

[Using Round?](http://msdn.microsoft.com/en-us/library/system.math.round(v=vs.71).aspx) — bzlm, Sep 18 '11 at 09:47
See http://stackoverflow.com/questions/14/whats-the-difference-between-math-floor-and-math-truncate-in-net/580252#580252 - it tells you everything you need to know about the various rounding and truncating methods. — paxdiablo, Sep 18 '11 at 09:53

Nawaz · Answer 1 · 2011-09-18T09:55:03.497

3

double d1 = Math.Round(1.2324); //d1 is 1
double d2 = Math.Round(1.898);  //d2 is 2

edited Sep 18 '11 at 09:55

answered Sep 18 '11 at 09:47

Nawaz

This compiles as an error "Cannot convert type double to decimal" – Henk Jansen Sep 18 '11 at 09:54
@1ntello: Sorry, the return type should be `double`, as the argument is `double`. – Nawaz Sep 18 '11 at 09:55

score 0 · Answer 2 · answered Sep 18 '11 at 09:49

0

answered Sep 18 '11 at 09:49

Radu

ok it worked thnx :) but if i want to approximate : 1.567 to 1.6 – Yasser Sep 18 '11 at 09:49
Multiply by 10, round, divide by 10. – Radu Sep 18 '11 at 09:52
@Yasser See here http://msdn.microsoft.com/en-us/library/system.math.round%28v=vs.71%29.aspx – Captain Giraffe Sep 18 '11 at 09:52

score 0 · Answer 3 · answered Sep 18 '11 at 09:54

0

Math.Round(double) does the trick. If you want to use a variable number of decimals behind the decimal point you can use Math.Round(double, int)

The API describing this is here.

answered Sep 18 '11 at 09:54

Oosterman

3 Answers3