const arr1 = [[1]]
const arr2 = arr1[0]
const temp = arr1.pop()
console.log(arr2)
temp.pop() // change happens here
console.log(arr2)Going a little crazy... why is arr2 being changed at the point I commented?
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1It's two variables (`arr2`, `temp`) holding a reference to the *same* array. – Bergi Jun 01 '22 at 01:57
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basically your code is the same as `const arr2 = arr1[0]` and `const temp = arr1[0]` – Bravo Jun 01 '22 at 01:58
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I guess I thought I was creating a new array instead of referencing the existing one. How would I create two separate arrays instead? – Henry Weigand Jun 01 '22 at 02:04
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This is due to mutation in Javascript. Use: const temp = [...arr1.pop()]; – subodhkalika Jun 01 '22 at 02:04
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Just read up on that, makes so much more sense now. Ty y'all – Henry Weigand Jun 01 '22 at 02:13