Getting 'command not found" error after compiling bash shell script

Asked May 15 '22 at 15:44

Active May 15 '22 at 15:50

Viewed 39 times

-1

I am trying to explore bash script using Linux Mint and I want to try conditional statement of math operation. But I am now stuck on error.

Here is the code

echo "Enter First Number: "
read numl 
echo "Enter Second Number: " 
read num2 
echo "Choose Operation Below" 
echo "1-Addition, 2-Subtraction, 3-Multiplication, 4-Division" 
read opr 

if [$opr == $(1)]
then 
    $answer=$((numl+num2)) 
    echo "Answer is $answer" 
fi

Now, I am getting an error

main.bash: line 9: 1: command not found
main.bash: line 9: [1: command not found

Where did I go wrong?

asked May 15 '22 at 15:44

Carl00001

1

As an aside, Bash is an interpreter; there is no "compilation". – tripleee May 15 '22 at 15:48
What's `$(1)` supposed to be? It looks like it should simply be `1`. – wjandrea May 15 '22 at 15:49
Also, `$answer=...` is wrong. In Bash, you assign to a variable without a dollar sign: `answer=...`. – wjandrea May 15 '22 at 15:49
Also, totally beside the point, but it looks like you have a typo: `numl` -> `num1`. – wjandrea May 15 '22 at 15:51
Tangentially, shell scripts should usually simply not have an extension. – tripleee May 15 '22 at 15:51

Getting 'command not found" error after compiling bash shell script

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