Create a regEx that validates birthdate including leap years

Asked May 12 '22 at 22:12

Active May 12 '22 at 22:12

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I was checking different regEx libraries to find one that helps me validate if a random date exists, including leap years. i found the following but it's not quite working since it's not written in python and I am writing the program in Python. Here's the code:

(^(((0[1-9]|1[0-9]|2[0-8])[\/](0[1-9]|1[012]))|((29|30|31)[\/](0[13578]|1[02]))|((29|30)[\/](0[4,6,9]|11)))[\/](19|[2-9][0-9])\d\d$)|(^29[\/]02[\/](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)

What should I change to make it work on Python. I'm currently getting a syntax error where the last set of round parentheses starts.

asked May 12 '22 at 22:12

JeremyK12

Curious, why would you use a RegExp for this? RegExp is specifically geared towards pattern matching and (most all implementations) don’t include any arithmetic facilities (numeric, dates, etc.) - that should be left to the application layer. – esqew May 12 '22 at 22:14
This is regex abuse. It is absolutely the wrong way to handle this. Extract the dates with a simple pattern, and use code to validate them. – Tim Roberts May 12 '22 at 22:14
I will try that, thanks! I was asked to do it with regEx so that's why I tried this way. – JeremyK12 May 12 '22 at 22:18
This works for me, but the expected format is dd/mm/yyyy, for dates from "01/01/1900" to "31/12/9999" – PaulMcG May 12 '22 at 22:19
On python? I get a syntax error – JeremyK12 May 12 '22 at 22:20
1

Quick! Could someone have been born on February 29, 1900? – Cary Swoveland May 12 '22 at 22:21
I think not, it wasnt a leap year – JeremyK12 May 12 '22 at 22:24

Create a regEx that validates birthdate including leap years

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