PHP - Get range boundaries from IPv6 and cidr

Question

I am trying to do a PHP function which retrieves range boundaries of an IPv6 when we gives it an IPv6 and its CIDR.

Example -> Parameter :

2001:0db8:85a3:0000:0000:8a2e:0370:7334/100

Example -> Expected result :

[
    [0] => "2001:db8:85a3::8a2e:0:0",
    [1] => "2001:db8:85a3::8a2e:fff:ffff"
]

I found it easily for an IPv4 but not for an IPv6. I tried most of the things found in Google, like this : https://localcoder.org/calculate-ip-range-using-php-and-cidr but got the following error when I tried with my CIDR. Warning: hex2bin(): Hexadecimal input string must have an even length.

I also tried this function :

$range = [];

$range[0] = $this->long2ip_v6(($this->ip2long_v6($ip)) & ((-1 << (128 - (int)$cidr))));
$range[1] = $this->long2ip_v6(($this->ip2long_v6($range[0])) + pow(2, (128 - (int)$cidr)) - 1);

return $range;

inspired for the one for IPv4, working with this functions to convert IPv6 : Php convert ipv6 to number

But I got the following error. gmp_init(): Argument #1 ($num) must be of type GMP|string|int, float given

So now I don't know what to do. How to retrieve boundaries of the range where a given IPv6 is inside please ?

PHP - Get range boundaries from IPv6 and cidr

0 Answers0