How to attach a string on php variable

Question

I am trying to attach a string on php variable this is my code

if ($tipy = "2"){
        $username = "dr_" + $username;
    }

and output to be dr_James

But this doesnt work gives me result as 0.

Should it be `==` in the if condition? – Chun Apr 29 '22 at 11:24 — Chun, Apr 29 '22 at 11:24
@Chun no you can check it also, it works for me – testedwho Apr 29 '22 at 11:37 — testedwho, Apr 29 '22 at 11:37

JrWebDev · Accepted Answer · 2022-04-29T11:31:07.267

0

You should use a dot.

if ($tipy = "2"){
        $username = "dr_" . $username;
    }

edited Apr 29 '22 at 11:31

answered Apr 29 '22 at 11:22

JrWebDev

Quick answer, but not very thorough. What about the if condition? – KIKO Software Apr 29 '22 at 11:23
Hi Kiko, if you check for a number than you should not check for a string. Instead use a number if ($tipy == 2){ $username = "dr_" . $username; } – JrWebDev Apr 29 '22 at 11:24
No, I mean it should probably be `==` (is equal) instead of `=` (assignment). – KIKO Software Apr 29 '22 at 11:25
The if condition is bad : if ($tipy == "2") -> (double = or triple for exact match) – svgta Apr 29 '22 at 11:25
@JrWebDev this worked but you dont need "==" one is enough its also in php. – testedwho Apr 29 '22 at 11:28
@testedwho If at least three people here doubt it should be `=` you should consider it could maybe be `==`. Yes, the assignment operator works, but it is highly unusual. – KIKO Software Apr 29 '22 at 11:31
In this case i have only 2 values 1 or 2 so i just check if tipy is 2 or not – testedwho Apr 29 '22 at 11:43
@testedwho: Yes, I understand that that is what you intend to do, but instead you're now assigning the value 2 to tipy. This means your condition is always true, regardless of what the value of tipy is. – KIKO Software Apr 29 '22 at 12:11

1 Answers1