when i copy or clone an array and make changes in new cloned array then the parent array data also change like;
var array1 = ['A','B','C'];
var array2 = array1;
array2.push('X');
//then;
array1 = ['A','B','C','X']
array2 = ['A','B','C','X']
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M YASIN
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You are making a shallow copy not a deep copy which resulting the modify of original array if any changes happen in instance – Rohìt Jíndal Apr 26 '22 at 11:58
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1You didn't clone the array. You simply assigned a reference to the (same) array to another variable. – CherryDT Apr 26 '22 at 11:58
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1@RohìtJíndal it's not even a shallow copy, it's no copy at all. (a shallow copy would work here) – CherryDT Apr 26 '22 at 11:59
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i found a solution by doing this. var array2 = JSON.parse(JSON.stringify(array1)) – M YASIN Apr 27 '22 at 04:46