Python super in local scope

Asked Apr 23 '22 at 12:42

Active Apr 23 '22 at 13:05

Viewed 24 times

I can't figure out why super().method() cannot be called from local scopes:

Correct code:

class A:
    def method(self):
        print('hello')

class B(A):
    def method(self):
        super().method()

B().method()

Error:

class A:
    def method(self):
        print('hello')

class B(A):
    def method(self):
        def f():
            super().method()
        f()

B().method()

Error output:

Traceback (most recent call last):
  File "D:\sample.py", line 12, in <module>
    B().method()
  File "D:\sample.py", line 10, in method
    f()
  File "D:\sample.py", line 9, in f
    super().method()
RuntimeError: super(): no arguments

edited Apr 23 '22 at 13:05

quamrana

33,740
12
54
68

asked Apr 23 '22 at 12:42

klapeyron

2

Please update your question with the full error traceback. – quamrana Apr 23 '22 at 12:43
already updated – klapeyron Apr 23 '22 at 12:44
2

Because it references the first argument to the function it's used in see e.g. https://stackoverflow.com/a/60423665/3001761 – jonrsharpe Apr 23 '22 at 12:44
Note that the problem is specifically with calling `super` with no arguments, not with using `super` at all. – chepner Apr 23 '22 at 12:44
Roughly speaking, `f` is defined "too late" for the *compiler* to determine what the arguments to `super` should be. – chepner Apr 23 '22 at 12:45
No, really, please update your question with the full error traceback. – quamrana Apr 23 '22 at 12:48
@jonrsharpe Are you not voting to close as a duplicate of your link for the same reason I'm not? (I think it's a good candidate, but I'm not willing to use my dupe hammer to close the question unilaterally.) – chepner Apr 23 '22 at 12:51
No, really, really, please update your question with the **full** error traceback. – quamrana Apr 23 '22 at 12:52

Python super in local scope

0 Answers0