Get variables from a a file in bash

Question

I have a file name inputfile having following data:

 database=mydb
 table=mytable
 partitions=p1,p2,p3

I pass this file as first argument as following:

 bash mybashfile.sh inputfile

I want to use this file in my bash script that input database, table and partitions as variables

I tried this by putting the whole content of myfile in a variable

  #!/bin/bash
  var=$(cat $1) 
  echo $var

I am new to bash script so I need help

Mime · Accepted Answer · 2022-04-21T12:36:40.427

3

Consider using source, which will load the variables from that file

#!/bin/bash
source "$1"
echo "$database"
# mydb
echo "$table"
# mytable
echo "$partitons"
# p1,p2,p3

For more information about source see this superuser-question

edited Apr 21 '22 at 12:36

answered Apr 21 '22 at 11:59

Mime

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6
15

If I need to input these variables using yaml file like database: mydb table: MYTABLE partitions: p1,p2,p3 . Any idea how can I do that – Rahul Sharma Apr 21 '22 at 12:11
`source – Mime Apr 21 '22 at 12:25

score 0 · Answer 2 · answered Apr 21 '22 at 12:05

You can read key, value pairs from a file with a while loop:

#!/bin/bash
declare -A kv     # declare an associative array

while IFS="=" read -r k v; do
    kv["$k"]="$v"
done < "file"

declare -p kv     # print the array

Prints:

declare -A kv=([table]="mytable" [database]="mydb" [partitions]="p1,p2,p3" )

Get variables from a a file in bash

2 Answers2