how to replace certain pattern with nothing in lists

Question

If a list looks like this:

['wo/od', 'axe/es']

and for replacing "/" with nothing "" I am using following code but its not working.

for lines in z:
    if lines == "/"
    lines.replace = ""

I am new to python Any help would be appreciated. I am also not allowed to hardcode it.

score 4 · Answer 1 · answered Apr 19 '22 at 06:12

4

Assuming that z is a reference to your list and bearing in mind that Python strings are immutable you could do this:

z = ['wo/od', 'axe/es']

z = [s.replace('/', '') for s in z]

answered Apr 19 '22 at 06:12

Albert Winestein

score 0 · Answer 2 · answered Apr 19 '22 at 06:19

0

I can see you are using replace in wrong way it should be

z = ['wo/od', 'axe/es']

for lines in z:
    lines = lines.replace("/","")
    print(lines)

answered Apr 19 '22 at 06:19

im_vutu

The OP wants to update the list with the new values, not print them. – Thierry Lathuille Apr 19 '22 at 06:22
Yes I got it wrong. OP said they are not allowed to hardcode the given example. And the given example is referencing each elements in loop as line rather than updating the list. So I kept the loop. Anyway the right answer is already given by Lancelot, so I am just keeping my answer as it is if someone wants to work with elements keeping the list as it is. – im_vutu Apr 19 '22 at 07:08

Avinash · Answer 3 · 2022-04-19T06:51:46.693

0

Try this:

a = ['wo/od', 'axe/es']
for i, line in enumerate(a):
    a[i] = line.replace('/', '')
print(a)

edited Apr 19 '22 at 06:51

answered Apr 19 '22 at 06:22

Avinash

You could simply call *replace()* unconditionally. If the value given as the first argument to *replace()* doesn't exist no error ensues – Albert Winestein Apr 19 '22 at 06:26
Thank you @LancelotduLac for pointing out. I've updated the code. – Avinash Apr 19 '22 at 06:53

3 Answers3