Is it possible to programmatically apply :active (not active class that is created) but the pseudoclass :active to a link?
In the past, creating my own class worked well but I am in need of a more seamless way of making the link active.
Is it possible to programmatically apply :active (not active class that is created) but the pseudoclass :active to a link?
In the past, creating my own class worked well but I am in need of a more seamless way of making the link active.