I am new to scripts, and I want to monitor top 2 process with high memory usage, and keep lists of processes that are not mysqld.
I wrote a script below,
lines=$(ps aux --sort rss | head -n 3)
echo $lines
for line in $lines
do
echo $line
done
and found out that it prints words instead of lines.
How can I save a line in the variable line?
You are not creating an array at all. The syntax for that would look like
lines=($(ps aux --sort rss | head -n 3))
where the inner $(...) is a command substitution which simply expands to a sequence of tokens (not lines!) and the outer parentheses declare an array.
Probably a much better solution entirely is to just loop over the output from ps directly. Collecting the results in an array is only useful if you need to traverse the values repeatedly for some reason (like sort them by different criteria, or loop over them multiple times).
ps aux --sort rss | head -n 3
or if you want to decorate the output further, perhaps
ps aux --sort rss | head -n 3 |
while IFS= read -r line; do
echo "the output was $line with proper quoting"
done
(though with a static decoration around the value, maybe simply prefer ps aux --sort rss | head -n 3 | sed 's/.*/the output was & with some decorations/').
With recent versions of Bash, you can read the values into an array with readarray -t.
readarray -t lines < <(ps aux --sort rss | head -n 3)
for line in "${lines[@]}"; do # notice proper array syntax
echo "$line" # notice proper quoting
done
The array syntax is slightly odd, but needs to be backwards-compatible with the original Bourne shell, where $lines will always refer to a single string value.
(readarray is Bash v4+ so not available e.g. on MacOS out of the box currently.)
