I ran the following in the python3 interpreter:
>>> d = dict( a=1, b=2 )
>>> [v for k,*v in d.items()]
[[1], [2]]
Why does using the star operator in this context cause each value to get wrapped in a list?
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wjandrea
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Zark Bardoo
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I failed to visually parse this correctly. The individual `int`s aren't magically getting wrapped in a `list`. Each key-value pair in `d.items()` is itself a sequence that is assigned to `k,*v` (e.g. `k,*v = 'a', 1`). – Zark Bardoo Mar 28 '22 at 17:14