Python Looping/Iterator logic

Asked Mar 08 '22 at 14:26

Active Mar 15 '22 at 16:51

Viewed 31 times

I have gone through ZIP function in python.

I copied this python code and did hands-on.

    list1 = ["c", "b", "d", "a"]
    list2 = [2, 3, 1, 4]
    zipped_lists = zip(list1, list2)
    
print('L')
    print(zipped_lists)
    #[print(ZipDa) for ZipDa in zipped_lists]

    sorted_pairs = sorted(zipped_lists)
    print('S')
    print(sorted_pairs)

    tuples = zip(*sorted_pairs)
    print('t')
    print(tuples)
    list1, list2 = [list(tuple) for tuple in tuples]
    print(list1)
    print(list2)

and got output as

L
<zip object at 0x000002485D55B000>
S
[('a', 4), ('b', 3), ('c', 2), ('d', 1)]
t
<zip object at 0x000002485D58BCC0>
['a', 'b', 'c', 'd']
[4, 3, 2, 1]

When i uncomment the line [print(ZipDa) for ZipDa in zipped_lists] i see the data in Zipped_List. but the sorted(zipped_lists) received empty list. Please refer below output.

L
<zip object at 0x000002026736B000>
('c', 2)
('b', 3)
('d', 1)
('a', 4)
S
[]
t
<zip object at 0x00000202673B1540>

Can you please share why after looping iterator send empty list ?

edited Mar 15 '22 at 16:51

CristiFati

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asked Mar 08 '22 at 14:26

RamK

2

because you've exhausted the iterator – Sayse Mar 08 '22 at 14:28
The values of an iterator are generated when we traverse them and after traversal it becomes empty. You can refer to this question for the behavior - https://stackoverflow.com/q/25039334 – anirudh sharma Mar 08 '22 at 14:32
ok, how to make the iterator available for next line. – RamK Mar 08 '22 at 14:32
@RamK make it a list instead of an iterator - `zipped_lists = list(zip(list1, list2))` – anirudh sharma Mar 08 '22 at 14:33

Python Looping/Iterator logic

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