I am getting index out of error in this in python

Question

I am having an array A=[9, 9, 3, 6, 3]. Why am I getting index out of range error?

def hello(A):
    A = set(A)
    A = list(A)
    A.sort()
    for i in range(len(A)):
        for j in range(1, len(A)):
            if A[j] % A[i] == 0:
                A.remove(A[j])
    return len(A)

You're iterating and modifying the array at the same time. Explain what you're trying to do exactly so we can provide a more accurate help. — tobihans, Mar 07 '22 at 06:20
actually i want to remove the elements which are multiple of any element for example i want only 3 in the list and remove rest of the elements, means [3]. — ABHISHEK SINGH, Mar 07 '22 at 06:24
@kraken for example for [4,8,5] i want [4,5] only. Since 8 is multiple of 4 — ABHISHEK SINGH, Mar 07 '22 at 06:25

wekular · Answer 1 · 2022-03-07T11:42:58.260

-1

def hello(A):
   A=set(A)
   A=list(A)
   A.sort()
   final_list = A.copy()      # copy the list 
   for i in range(len(A)):
       for j in range(1,len(A)):
            if(A[j]%A[i]==0):
                if A[j] in final_list:
                    final_list.remove(A[j])  # removed from the copied list instead original list A
   return final_list

edited Mar 07 '22 at 11:42

answered Mar 07 '22 at 06:27

wekular

67
7

Please explain what you changed in the code and how it solves the problem. – BDL Mar 07 '22 at 10:08
@BDL added the comment where changes needs to be done. – wekular Mar 07 '22 at 11:43

I am getting index out of error in this in python

1 Answers1