Regex optional characters at end of string

Asked Feb 18 '22 at 15:53

Active Feb 18 '22 at 18:45

Viewed 28 times

I have this regex expressions:

/^_string-(.*)-(-?[0-9]+)$/

which would match 3 parts for this example:

'_string-hello-599' ['string-hello-599', 'hello', '599']

I would like to make the last part optional -(-?[0-9]+), so that I could also match for example '_string-goodbye'.

This gives me 'unsafe regex' errors:

/^_string-(.*)(-(-?[0-9]+))?$/

What is the correct way to do it?

edited Feb 18 '22 at 15:58

asked Feb 18 '22 at 15:53

warrenfitzhenry

Did you mean to put `$` in front of `/`? Also, you need a lazy `.*?` in Group 2. Try just `/^_string-(.*?)(?:-(-?[0-9]+))?$/` – Wiktor Stribiżew Feb 18 '22 at 15:55
Or match word characters, and if you want to match a single hyphen make it optional as a whole part `^_string-(\w+)(-[0-9]+)?$` – The fourth bird Feb 18 '22 at 15:56

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